Respuesta :
Answer: (-1,-6)
Step-by-step explanation:
x^2+6x+3
g(x) = f(x-2)
replace all value of x in the f(x) function to (x-2)
(x-2)^2 + 6(x-2) + 34
(x-2)(x-2) + 6(x-2) + 34
expand through FOIL and distribution
x^2-4x+4+6x-12+3
combine like terms
x^2+2x-5
-b/2a = x value of vertex
-2/2(1) = x value
x value = -1
plug in -1 for all values of x in the g(x) equation to solve for y value
(-1)^2+2(-1)-5
1-2-5 = -6
y = -6
x = -1
(x,y) = (-1,-6)
The vertex of the considered function g(x) = f(x − 2) is given by: Option c: (-1,-6)
What is vertex form of a quadratic equation?
If a quadratic equation is written in the form
[tex]y=a(x-h)^2 + k[/tex]
then it is called to be in vertex form. It is called so because when you plot this equation's graph, you will see vertex point(peak point) is on (h,k)
This point (h,k) is called the vertex of the parabola that quadratic equation represents.
How to convert the given equation to vertex form?
We first take out coefficient of x squared, and then inside the bracket, we try to make perfect square like situation.
So, we're given that:
- [tex]f(x) = x^2 + 6x + 3[/tex]
- [tex]g(x) = f(x-2)[/tex]
Thus, we get:
[tex]g(x) = f(x-2) \\g(x) = (x-2)^2 + 6(x-2) + 3 \\g(x) = x^2 -4x + 4 + 6x - 12+3\\ g(x) = x^2 + 2x -5[/tex]
Converting g(x) to vertex form:
[tex]g(x) = x^2 + 2x - 5\\g(x) = x^2 + 2x + 1 - 1 -5\\g(x) = (x+1)^2 -9\\g(x) = (x - (-1) )^2 -6\\g(x) = (x-(-1))^2 + (-6)[/tex]
Comparing this with [tex]a(x-h)^2 + k[/tex], we get (h,k) = (-1,-6) as the coordinate of the vertex of the graph of g(x), as shown below.
Thus, the vertex of the considered function g(x) = f(x − 2) is given by: Option c: (-1,-6)
Learn more about vertex form of a quadratic equation here:
https://brainly.com/question/9912128
