When the ball on a spring is replaced by a smaller ball with half the mass : The period decrease by 29%
Calculate the Period
We will apply the formula below to calculate period
T = [tex]2\pi \sqrt{\frac{m}{k } }[/tex]
where :
T₁ / T₂ = [tex]\sqrt{\frac{m_{1} }{m_{2} } }[/tex] where m₂ = m₁ / 2
Therefore :
T₂ = [tex]\frac{T_{1} }{\sqrt{2} }[/tex] = 0.71 T
Hence we can conclude that the period will decrease by 29% ( i.e 100 - 71 ).
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