Answer:
497 m (nearest whole number)
Step-by-step explanation:
As the problem has been modeled as a right triangle, we can use the sine trigonometric ratio to find the distance d.
Sine trigonometric ratio
[tex]\sf \sin(\theta)=\dfrac{O}{H}[/tex]
where:
- [tex]\theta[/tex] is the angle
- O is the side opposite the angle
- H is the hypotenuse (the side opposite the right angle)
From inspection of the given diagram:
- [tex]\theta[/tex] = 38°
- O = 306 m
- H = d
Substitute the values into the formula and solve for d:
[tex]\implies \sf \sin(38^{\circ})=\dfrac{306}{H}[/tex]
[tex]\implies \sf H=\dfrac{306}{\sin(38^{\circ})}[/tex]
[tex]\implies \sf H=497.0263891...[/tex]
Therefore, the distance d between the helicopter and the landing pad is 497 m (nearest whole number).
