Answer: ( -[tex]\sqrt{5}[/tex] / 3)
Step-by-step explanation:
sin(angle) = opposite/hypotenuse
opposite =2
hypotenuse = 3
solve for adjacent side with pythagorean theorum
opposite^2 + adjacent^2 = hypotenuse^2
2^2 + adjacent^2 = 3^2
4 + adjacent^2 = 9
adjacent^2 = 9 - 4
adjacent^2 = 5
adjacent = [tex]\sqrt{5}[/tex]
-[tex]\sqrt{5}[/tex] since it is in the second quadrant
cosx = (adjacent/hypotenuse)
cosx = (-[tex]\sqrt{5}[/tex]/3)
(-[tex]\sqrt{5}[/tex]/3)
