Two people meet in the conference room on the fourth floor of a building. On departure, one person travels West
24 feet, South 18 feet, and Down 18 feet. The other person travels North 24 feet, East 12 feet, and Up 18 feet.
How far apart are the two people? Round to the nearest tenth.

Respuesta :

Ata258

Answer:

36*(5)^0.5

Step-by-step explanation:

distance on horizontal  36 feet

distance on vertical 78 feet

so distance between them = (36^2+78^2)^0.5 = 36*(5)^0.5

The two people are 66 feet apart from each other.

How to elaborate the problem ?

The 1st person travels 24 feet west, 18 feet south and 18 feet down.

The location of 1st person is (-24, -18, -18) , the negative sign is to convert all in same direction.

The 2nd person travels 12 feet east, 24 feet north and 12 feet up.

The location of 2nd person is (12, 24, 18)

How to find the distance between them ?

The distance between  (-24, -18, -18) & (12, 24, 18 = [tex]\sqrt{(-24-12)^{2}+(-18-24)^{2}+(-18-18)^{2} }[/tex] feet

= [tex]\sqrt{(-36)^{2}+(-42)^{2}+(-36)^{2} }[/tex]) feet

= 66 feet

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