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A gas occupies 9 L at a temperature of 325K. What is the volume at 450?
O 125L
ОЗК
O 302
O 87 L

Respuesta :

samueladesida43

The volume of a gas that occupies 9 L at a temperature of 325K is 12.46L.

How to calculate volume?

The volume of a given gas can be calculated using the following Charle's law equation:

V1/T1 = V2/T2

Where;

  • T1 = initial temperature
  • T2 = final temperature
  • V1 = initial volume
  • V2 = final volume

  • V1 = 9L
  • V2 = ?
  • T1 = 325K
  • T2 = 450K

9/325 = V2/450

325V2 = 4050

V2 = 4050/325

V2 = 12.46L

Therefore, the volume of a gas that occupies 9 L at a temperature of 325K is 12.46L.

Learn more about volume at: https://brainly.com/question/2817451

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