From the calculations;
The equations of motion are used in kinematics to obtain the various variables that has to do with motion.
In this case;
distance covered = 30 ft
initial velocity = 40 ft/second
Final velocity = 0 m/s at the maximum height
Hence;
v^2 = u^2 - 2gh
since v = 0
u^2 = 2gh
h = u^2/2g
h = (40)^2/2(9.8)
h = 82 feet
highest point above the ground = 82 feet + 30 feet = 112 feet
Now;
v = u - gt
since v = 0
u = gt
t = u/g
t = 40/9.8
t = 4 seconds
Time taken to hit the ground = 2(4 seconds) = 8 seconds
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