For a system of four capacitors is connected across a 90-V voltage source, the potential difference across the plates of the 6.0-µF and 2uF capacitors is mathematically given as
a) vd=30v
b) Q=119.7uc
Generally, the equation for the charge across 6uf is mathematically given as
Q=C6Vd
Where
1/c36=1/3+1/6
c36=2
Q3=2*90
Q3=180
Therefore
vd=180/6
vd=30v
In conclusion
1/c24=1/2+1/4
C24=1.33uf
Q2=1.33*90
Q=119.7uc
Read more about Charge
https://brainly.com/question/9156412