Respuesta :

[tex]\left(\dfrac{(-1)^5}{(-2)^{-3}} \right)^2\\\\\\=\left(\dfrac{-1}{\dfrac{1}{(-2)^3}} \right)^2\\\\\\=\left(-1 \times -8\right)^2\\\\=8^2\\\\=64[/tex]

Answer:

[tex]\huge\boxed{\bf\:64}[/tex]

Step-by-step explanation:

[tex]\left(\frac{(-1)^{5}}{\left(-2\right)^{-3}}\right)^{2}[/tex]

Now, simplify [tex](-1)^{5} = -1[/tex]. Then,

[tex]\left(\frac{-1}{\left(-2\right)^{-3}}\right)^{2}[/tex]

Calculate: [tex](-2)^{-3} = \frac{1}{(-2)^{3}} = - \frac{1}{8}[/tex].

[tex]\left(\frac{-1}{-\frac{1}{8}}\right)^{2}[/tex]

Divide [tex]-1[/tex] by [tex]- \frac{1}{8}[/tex]. The result will be [tex]8.[/tex]

[tex]\left(-\left(-8\right)\right)^{2} \\= 8^{2}[/tex]

Calculate [tex]8[/tex] to its square which is [tex]64.[/tex]

[tex]8^{2}\\=\boxed{\bf\: 64} \: \:\mathrm{(3^{rd} \: option)}[/tex]

[tex]\rule{150pt}{2pt}[/tex]

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