evanslambert1
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For circle B, BG = BE, BG is perpendicular to DC, and BE is perpendicular to FA. What conclusion can be made? a circle with center B and chords DC and FA, a segment from B to chord DC intersect chord DC at G, and a segment from B to chord FA intersects chord FA at E segment DC is parallel to segment FA segment CD is congruent to segment EB segment GB is parallel to segment EB segment DC is congruent to segment FA

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akposevictor

Base on the equidistant chords theorem, chords FB and DA are congruent because they are equidistant from C.

What is the Equidistant Chords Theorem?

The equidistant chords theorem states that two chords in the same circle are congruent to each other, if they are equidistant from the center of the circle.

Thus, based on the information given we can conclude that chords FB and DA are congruent because they are equidistant from C based on the equidistant chords theorem.

Learn more about the equidistant chords theorem on:

https://brainly.com/question/7511582

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