Using it's concept, it is found that the probability that an ID code does not contain the letter I is given by:
A. 0.9246
A probability is given by the number of desired outcomes divided by the number of total outcomes.
Considering that for each letter there are 26 possible outcomes and for each digit there are 10 possible outcomes, the total number of outcomes is given by:
T = 26 x 26 x 10 x 10 x 10 x 10 = 6,760,000.
Without the letter "l", the desired number is given by:
D = 25 x 25 x 10 x 10 x 10 x 10 = 6,250,000.
Hence, the probability is given by:
p = 6,250,000/6,760,000 = 0.9246.
Which means that option A is correct.
More can be learned about probabilities at https://brainly.com/question/14398287
