Respuesta :

for this equation we just use pythagorean theorem.

11^2+12^2=x^2
121+144=x^2
265=x^2
x=16.3
DᴀʀᴋPᴀʀᴀᴅᴏx

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Let's use Pythagoras theorem !

[tex]\qquad \sf  \dashrightarrow \:h {}^{2} = p {}^{2} + b {}^{2} [/tex]

where,

  • h = hypotenuse = unknown

  • b = base = 11

  • p = perpendicular = 12

[tex]\qquad \tt\dashrightarrow \:h {}^{2} = 12{}^{2} + 11 {}^{2} [/tex]

[tex]\qquad \tt\dashrightarrow \:h {}^{2} = 144{}^{} + 121[/tex]

[tex]\qquad \tt\dashrightarrow \:h {}^{2} = 265[/tex]

[tex]\qquad \tt\dashrightarrow \:h {}^{} = \sqrt{265}[/tex]

[tex]\qquad \tt\dashrightarrow \:h {}^{} \approx16.3[/tex]

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