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Making auto parts A grinding machine in an auto
parts plant prepares axles with a target diameter
p = 40.125 millimeters (mm). The machine has
some variability, so the standard cleviation of tlic
diameters is a = 0.002 mm. The machine operator
inspects a random sample of 4 uxles cach hour for
quality control purposcs and records llic sample
mcan diameter 1. Assuming that the process is work-
ing properly, what are the mean and standard devia I
fion of the sampling distribution of ? Explain.

Respuesta :

Snor1ax

Answer: See below

Step-by-step explanation:

Mean:

Since the sample is taken from a large population it follows the central limit theorem, which states that the sample mean is approximately equal to the population mean.

Therefore: [tex]\bold{\bar{X}=\mu=40.125}[/tex]

Standard Deviation:
Again by central limit theorem the standard deviation of the sample is calculated as:

[tex]S=\frac{\sigma}{\sqrt{n}}[/tex]

Since n=4, therefore

S = 0.001

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