Altitude (AB) = 6cm
Base (BC) = 8cm
Hypotenuse (AC) = ?
[tex] \fbox \text{According To Pythagoras Theorem = }[/tex]
[tex] \text{(Hypotenuse)² = (Altitude)² + (Base)²}[/tex]
Inserting The Values
[tex] \text{(Hypotenuse)²} =( {6})^{2} + (8) {}^{2} [/tex]
[tex] (\text{AC}) {}^{2} = (6) {}^{2} + (8) {}^{2} \\ \implies \text{(AC)} {}^{2} = 36 + 64 \\ \implies\text{AC} = \sqrt{100} \\ \implies\text{AC} = 10 \\ \\ \therefore \text{Hypotenuse (AC)} = 10 \text{cm}[/tex]
Correct Option D= 10cm
