Hello There!!
Given:-
Altitude (AB) = 9cm
Base (BC) = 12cm
To Find
Hypotenuse (AC) = ?
[tex] \fbox \text{According To Pythagoras Theorem = }[/tex]
[tex] \text{(Hypotenuse)² = (Altitude)² + (Base)²}[/tex]
Inserting The Values
[tex] \text{(Hypotenuse)²} =( {9})^{2} + (12) {}^{2} \\ \\ \implies \text{(AC)} {}^{2} = 81 + 144 \\ \\ \implies \text{(AC}) {}^{2} = 225 \\ \\ \implies \text{AC} = \sqrt{225} \\ \\ \implies \text{AC} = 15[/tex]
[tex] \therefore \text{Hypotenuse \: (AC)} = 15 \text{cm}[/tex]
Option B= 15cm is the correct answer
Hope This Helps
