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A 76.89 g sample of a hydrocarbon(CxHy) has a mass of hydrogen that is equal to 10.45 g. Given this information, determine the empirical formula of this hydrocarbon. {MMC=12.01 and MMH=1.008}.

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TillyMatilda

Answer:

the empirical formula will be CH2

Explanation:

C

[tex] = \frac{66.44}{12} \\ = \frac{5.536}{5.536} \\ = 1 \\ = 1 \\ h \\ \frac{10.45}{1} \\ = \frac{10.450}{5.536} \\ = 1.88 \\ = 2[/tex]

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