What is the value of b?

Answer:
24
Step-by-step explanation:
In triangle STU, line VT bisects angle STU.
-> By angle bisector theorem:
[tex] \frac{67}{2b} = \frac{67}{b + 24} \\ \\ \implies \: \frac{1}{2b} = \frac{1}{b + 24} \\ \\ \implies \: 2b = b + 24 \\ \\ \implies \: 2b - b = 24 \\ \\ b = 24[/tex]
The value of b is 24
If we consider a triangle TSU, Let the angle bisector of angle T intersect side SU at a point V between S and U. The angle bisector theorem states that the ratio of the length of SV to the length of VU is equal to the ratio of the length of ST to the length of TU.
i.e. [tex]\frac{|SV|}{|VU|}=\frac{|ST|}{|TU|}[/tex]
Here, given that, SV = 2b, VU = b+24, ST = TU = 67
∴ [tex]\frac{|SV|}{|VU|}=\frac{|ST|}{|TU|}[/tex]
⇒ [tex]\frac{2b}{b+24}=\frac{67}{67}[/tex]
⇒ [tex]\frac{2b}{b+24}=1[/tex]
⇒ 2b = b+24
⇒ b = 24
Hence, b = 24
Learn more about Angle bisector theorem here :
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