Answer: x = -8, x = [tex]\frac{3}{2}[/tex]
Step-by-step explanation:
This is a quadratic equation since it is in ax² + bx + c = 0 form! We will use the formula and use PEMDAS, the order of operations, while solving as well.
The quadradic formula, then plugging in to solve:
(please note before the square root is a ± sign. Brainly text editor will not allow me to add it)
[tex]x = \frac{-b\sqrt{b^{2} -4ac } }{2a}[/tex]
[tex]x = \frac{-13\sqrt{13^{2} -4(2)(-24) } }{2(2)}[/tex]
[tex]x = \frac{-13\sqrt{169 -4(2)(-24) } }{4}[/tex]
[tex]x = \frac{-13\sqrt{169 +192 } }{4}[/tex]
[tex]x = \frac{-13\sqrt{361 } }{4}[/tex]
Now it breaks into two parts:
[tex]x = \frac{-13-19}{4}[/tex] and [tex]x = \frac{-13+19}{4}[/tex]
[tex]x = \frac{-32 }{4}[/tex] [tex]x = \frac{6}{4}[/tex]
x = -8, x = [tex]\frac{3}{2}[/tex]
