Answer:
[tex]\fbox{Surface \: area \: of \: prism = 520 \: sq.in.} [/tex]
Step by step explanation:
Given:
height of prism h = 10 in
length of base of triangle b = 8 in
height of triangle h' = 15in
side A of triangle = 17 in
To find:
Surface area of prism = ?
Solution:
[tex]\begin{gathered}Area \: of \: base \: triangle = \: \frac{1}{2}\cdot{b}{h'} \\ Area \: of \: base \: triangle = \frac{1} {\not2}\cdot{15} \times \not{8} \\ Area \: of \: base \: triangle = 60 \: {in}^{2} \end{gathered}[/tex]\\[tex]\fbox{Area \: of \: base \: triangle \: (B) = 60 \: sq.in. }\\\begin{gathered}Perimeter \: of \: base \: triangle = Side A + Height \: h' + base \: b \\ Perimeter \: of \: base \: triangle = 15 + 17 + 8 \: in\\ Perimeter \: of \: base \: triangle = 40 \: in\end{gathered}
[/tex]
[tex]\fbox{Perimeter \: of \: base \: triangle (p) \: = 40 \: in} [/tex]
[tex]\begin{gathered}Surface \: area \: of \: prism = 2B+ \: ph \\ Surface \: area \: of \: prism = 2 \times 60+ \: 40 \times 10 \\ Surface \: area \: of \: prism = 120 + 400\\ Surface \: area \: of \: prism = 520 \: {in}^{2} \end{gathered} [/tex]
[tex]\fbox{Surface \: area \: of \: prism = 520 \: sq.in.} [/tex]
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