The equation of the circle is (d) (x -3)^2 +(y - 1)^2 = 58
How to determine the circle equation?
The given parameters are:
- Center, (a,b) = (3,1)
- Point, (x,y) = (0,-6)
Start by calculating the radius using:
r^2 = (x -a)^2 +(y - b)^2
So, we have:
r^2 = (0 -3)^2 +(-6 - 1)^2
Evaluate
r^2 = 58
The circle equation is then calculated using:
(x -a)^2 +(y - b)^2 = r^2
This gives
(x -3)^2 +(y - 1)^2 = 58
Hence, the equation of the circle is (d) (x -3)^2 +(y - 1)^2 = 58
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