without further ado
10% of 36000 is simply 3600, we chopped a "0" off of it hmmm, ok so
[tex]~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$3600\\ r=rate\to 6.25\%\to \frac{6.25}{100}\dotfill &0.0625\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\dotfill &4\\ t=years\dotfill &15 \end{cases} \\\\\\ A=3600\left(1+\frac{0.0625}{4}\right)^{4\cdot 15}\implies A=3600(1.015625)^{60}\implies A\approx 9126.53[/tex]
