contestada

How many milliliters of a 1 M nitric acid solution are required to prepare 60 mL of 0.15 M solution?
Select the correct answer below:
400 mL
O 9 mL
O 0.25 mL
none of the above

Respuesta :

shaden7
9 mL
Explaination:
V1= m2*v2/m1 = 60 x 0.15 /1 = 9 mL