Answer:
heya! ^^
[tex]2x {}^{3} = x {}^{2} + 6x \\ \\ 2x {}^{3} = x(x + 6) \\ \\ dividing \: both \: sides \: by \: x \\ \\ \frac{2\cancel{x} {}^{3} }{\cancel{x}} = \frac{\cancel{x}(x + 6)}{\cancel{x}} \\ \\ 2x {}^{2} = x + 6 \\ \\ 2x {}^{2} - x - 6 = 0 \\ \\ by \: splitting \: the \: middle \: term \: ( - x) \\ \\ 2x {}^{2} - 4x + 3x - 6 = 0 \\ \\ 2x(x - 2) + 3(x - 2) = 0 \\ \\ 2x + 3 = 0 \: \: \: or \: \: \: (x - 2) = 0 \\ \\ x = \frac{ - 3}{2} \: \: \: \: or \: \: \: \: x = 2[/tex]
hope helpful :D
