Hello there!
In order to solve this inequality, we should first use the distributive property:-
3(a-4)≥4(a+5)
3a-12≥4a+20
Now, add 12 to both sides:-
3a≥4a+32
Subtract 4a from both sides:-
3a-4a≥32
-a≥32
Divide both sides by -1:-
a≤-32
The inequality sign changed because we divided both sides by a negative number.
[tex]\mathcal{NOTE:-}[/tex]
I hope everything is clear; however, if you need any explanation or clarification, don't hesitate to let me know, and I will comment or edit my answer. Good luck and have a great rest of your day! :)
