The ratio of the area of the first figure to the area of the second figure is 4:1
Ratio of the areas of similar figures
From the question, we are to determine the ratio of the area of the first figure to the area of the second figure
The two figures are similar
From one of the theorems for similar polygons, we have that
If the scale factor of the sides of two similar polygons is m/n then the ratio of the areas is (m/n)²
Let the base length of the first figure be ,m = 14 mm
and the base length of the second figure be, n = 7 mm
∴ The ratio of their areas will be
[tex](\frac{14 \ mm}{7 \ mm})^{2}[/tex]
[tex]= \frac{196 \ mm^{2} }{49\ mm^{2} }[/tex]
[tex]=\frac{4}{1}[/tex]
= 4:1
Hence, the ratio of the area of the first figure to the area of the second figure is 4:1
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