Answer:
[tex]\fbox{(a+b) and (a+b+1) are the factors}[/tex]
Step-by-step explanation:
Given equation = a² + 2ab + b² + a + b
Let's factorise,
We know that,
[tex]{(a + b)}^{2} = {a}^{2} + 2ab + {b}^{2} [/tex]
Substituting the above factor in given equation,
[tex] {a}^{2} + 2ab + {b}^{2} + a + b = {(a + b)}^{2} + a + b \\ Taking \: (a+b) \: common \: in \: RHS \\ {a}^{2} + 2ab + {b}^{2} + a + b = (a + b)(a + b + 1) \\[/tex]
[tex]\fbox{(a+b) and (a+b+1) are the factors}[/tex]
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