Respuesta :
The distribution of the trees in the landscape company is an illustration of probability
- The probability that all 4 winners will select the same type of tree is 0.0341
- The probability that 3 pine trees will be selected and the other tree will be a maple is 0.0710
- The probability that no fruit trees and 2 of each of the others will be selected is 0.0904
a. The probability that all 4 winners will select the same type of tree?
The distribution of the trees are:
- Fruit trees = 8
- Pine trees = 13
- Maple trees = 14
Total = 8 + 13 + 14
Total = 35
The probability is then calculated as:
P(Same type) = P(All fruit trees) + P(All pine trees) + P(All maple trees)
So, we have:
P(Same type) = (8/35 * 7/34 * 6/33 * 5/32) + (13/35 * 12/34 * 11/33 * 10/32) + (14/35 * 13/34 * 12/33 * 11/32)
Evaluate
P(Same type) = 0.0341
Hence, the probability that all 4 winners will select the same type of tree is 0.0341
b. The probability that 3 pine trees will be selected and the other tree will be a maple?
The probability is then calculated as:
P(3 pine and one maple) = 4 * P(Three maple and One Pine)
So, we have:
P(3 pine and one maple) = 4 * (13/35 * 12/34 * 11/33 * 13/32)
Evaluate
P(3 pine and one maple) = 0.0710
Hence, the probability that 3 pine trees will be selected and the other tree will be a maple is 0.0710
c. The probability that no fruit trees and 2 of each of the others will be selected?
The probability is then calculated as:
P(2 pine and 2 maple) = 4 * P(Two pine and Two maple)
So, we have:
P(2 pine and 2 maple) = 4 * (13/35 * 12/34 * 14/33 * 13/32)
Evaluate
P(2 pine and 2 maple) = 0.0904
Hence, the probability that no fruit trees and 2 of each of the others will be selected is 0.0904
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