gabrielaceleste04
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Please someone help!!!!
Kristine observes the top of a lookout tower from a point 220 ft from its base.

If the indicated angle of elevation measures 37º, how tall is the tower? Give your answer to the nearest tenth of a foot.

Please someone help Kristine observes the top of a lookout tower from a point 220 ft from its base If the indicated angle of elevation measures 37º how tall is class=

Respuesta :

fieryanswererft

Answer:

height of the tower: 165.8 ft

use tan rule:

[tex]\sf \sf tan(x)= \dfrac{opposite}{adjacent}[/tex]

Here:                            [ your calculator should be in degree mode [D] ]

  • x = 37°
  • opposite = height of the tower
  • adjacent = 220

Solve:

[tex]\hookrightarrow \sf \sf tan(37)= \dfrac{t}{220}[/tex]

[tex]\hookrightarrow \sf t = \sf tan(37)*220[/tex]

[tex]\hookrightarrow \sf t = 165.8 \ ft[/tex]

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