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The velocity as a function of time of a moving particle is given by v = α+ βt2 , where α and β are constants and t is time in s. What is the acceleration of the particle at 3 s?​

Respuesta :

adioabiola

The acceleration of the particle at 3s is [tex]a = 6 \beta [/tex]

[tex]v = \alpha + \beta {t}^{2} [/tex]

How to calculate acceleration

[tex]a = \frac{dv}{dt} \\ v = \alpha + \beta {t}^{2} \\ \frac{dv}{dt} = 0 + 2 \beta t \\ [/tex]

if Time is given as 3s

therefore, Acceleration is

[tex]a = 2 \beta t \\ a = 2 \beta 3 \\ a = 2 \times \beta \times 3 \\ a = 6 \beta [/tex]

Acceleration is

[tex]a = 6 \beta [/tex]

What is acceleration and velocity?

This is the change in velocity with respect to time.

Velocity is a vector quantity that denotes the rate of change of position with respect to time, or a speed with the directional component.

Read more about velocity:

https://brainly.com/question/19365526

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