The critical value becomes 2.584 for two tailed test since we have to reject the null hypothesis, t >2.584 or t < -2.584 test stat lie in the rejection region.
Data;
Let's calculate the t-value
[tex]t = \frac{x - \mu}{\frac{s}{\sqrt{n} } }[/tex]
Substitute the values into the equation and solve;
[tex]t = \frac{x - \mu}{\frac{s}{\sqrt{n} } } \\t = \frac{5.82 - 5}{\frac{4.93}{\sqrt{600} }} \\t = \frac{0.82}{0.201} \\t = 4.079[/tex]
The t-value is 4.079.
The allowed significance value = 0.01
The degree of freedom is n -1, which becomes 600 - 1 = 599.
The critical value becomes 2.584 for two tailed test since we have to reject the null hypothesis, t >2.584 or t < -2.584 test stat lie in the rejection region, we have to reject the null hypothesis or claim incorrect.
Learn more on t-test here;
https://brainly.com/question/6501190
