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WILL GIVE BRAINLIEST !! I NEED HELP ASAP

In the figure, ABCD is a rhombus.BG and DCG are straight lines

Find CAD
Find ACG

WILL GIVE BRAINLIEST I NEED HELP ASAP In the figure ABCD is a rhombusBG and DCG are straight lines Find CAD Find ACG class=

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Answer:

Below in bold.

Step-by-step explanation:

1) as ABCD is a rhombuc AC bisects < BAD and < BCD .

Therefore < CAD = 1/2 * 104 = 52 degrees.

2) < ACG  = < ADC +  < CAD  ( External angle of triangle theorem)

Therfore  < ACG = 76 + 52 = 128 degrees.

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