The coordinates of the point equidistant from their position is C(x,y) = (2, 3) and the equation of the locus is (x - 2)² + (y - 3)² = 2.
The center is the point that is equidistant to every point on the circumference. First, we need to determine the coefficients of the general equation of the circle, whose form is described below:
x² + y² + D · x + E · y + F = 0 (1)
We need three distinct points of the circumference to determine one solution.
If we know that (x₁, y₁) = (1, 2), (x₂, y₂) = (3, 4) and (x₃, y₃) = (3, 2), then the system of linear equations is:
D + 2 · E + F = -5 (2)
3 · D + 4 · E + F = - 25 (3)
3 · D + 2 · E + F = - 13 (4)
The solution of the linear system is D = - 4, E = - 6 and F = 11.
Now we proceed to transform the expression into its standard form by completing the squares:
x² + y² - 4 · x - 6 · y + 11 = 0
(x² - 4 · x + 4) + (y² - 6 · y + 9) - 2 = 0
(x - 2)² + (y - 3)² = 2
The coordinates of the point equidistant from their position is C(x,y) = (2, 3) and the equation of the locus is (x - 2)² + (y - 3)² = 2.
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