Answer:
[tex]\sf \dfrac13[/tex]
Step-by-step explanation:
From the table:
- Total number of Boys = 12
- Total number of students = 30
- Total number of Boys who are Freshman = 4
[tex]\sf Probability \ of \ an \ event \ occurring = \dfrac{Number \ of \ ways \ it \ can \ occur}{Total \ number \ of \ possible \ outcomes}[/tex]
[tex]\sf \implies P(Boy)=\dfrac{12}{30}[/tex]
[tex]\sf \implies P(Freshman \cap Boy)=\dfrac{4}{30}[/tex]
[tex]\begin{aligned}\sf P(Freshman|Boy) & = \sf\dfrac{P(Freshman \cap Boy)}{P(Boy)}\\\\ & = \sf\dfrac{4}{30} \div \dfrac{12}{30}\\\\ & = \sf\dfrac{4}{30}\times \dfrac{30}{12}\\\\ & = \sf \dfrac{4}{12}\\\\ & = \sf\dfrac{1}{3}\end{aligned}[/tex]