Solve for x and round to the nearest tenth for both (please:) )


Answer:
see explanation
Step-by-step explanation:
using the sine ratio in the right triangle.
sin23° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{x}{7}[/tex] ( multiply both sides by 7 )
7 × sin23° = x , then
x ≈ 2.7 ( to the nearest tenth )
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using the tangent ratio in the right triangle
tan x = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{27}{17}[/tex] , then
x = [tex]tan^{-1}[/tex] ( [tex]\frac{27}{17}[/tex] ) ≈ 57.8° ( to the nearest tenth )