Answer:
[tex]\sf \dfrac{1}{10}[/tex]
Step-by-step explanation:
From the table:
- Total number of Sophomores = 10
- Total number of students = 37
- Total number of Boys who are Sophomores = 1
[tex]\sf Probability \ of \ an \ event \ occurring = \dfrac{Number \ of \ ways \ it \ can \ occur}{Total \ number \ of \ possible \ outcomes}[/tex]
[tex]\sf \implies P(Sophomore)=\dfrac{10}{37}[/tex]
[tex]\sf \implies P(Boy \cap Sophomore)=\dfrac{1}{37}[/tex]
[tex]\begin{aligned}\sf P(Boy | Sophomore) & = \sf\dfrac{P(Boy \cap Sophomore)}{P(Sophomore)}\\\\ & = \sf \dfrac{1}{37} \div \dfrac{10}{37}\\\\ & = \sf\dfrac{1}{37} \times\dfrac{37}{10}\\\\ & = \sf\dfrac{1}{10}\end{aligned}[/tex]
