Answer:
Step-by-step explanation:
a) x be the height of the wall
[tex]tan \ 14 =\dfrac{opposite \ side}{adjacent \ side}\\\\\\0.2493 = \dfrac{3}{x}\\\\\\x*0.25 = 3\\\\x = \dfrac{3}{0.25}\\\\\\x = 12 ft[/tex]
b) Let y be the hieght of the wall
[tex]Sin \ 75 = \dfrac{opposite \ side}{hypotenuse}\\\\\\0.9659 = \dfrac{y}{15}\\\\\\0.97*15=y\\\\[/tex]
y = 14.6 ft
c) Let the angle formed between the bottom of the ladder to the ground be 'x'
[tex]Cos \x =\dfrac{adjacent \side}{hypotenuse}\\\\Cos \ x =\dfrac{3}{20}\\\\\\Cos \x = 0.15\\\\x = Cos^{-1} \ (0.15)\\\\[/tex]
x = 81°
No, the angle formed between the ground and the ladder is not safe as it is more than 70°
Let the farthest possible distance ladder placed from the wall be 'y'
[tex]Cos \ 70 =\dfrac{adjacent \ side }{hypotenuse}\\\\0.342 = \dfrac{y}{20}\\\\0.3*20=y[/tex]
y = 6 ft
6 ft is the furthest possible distance the ladder can be placed to maintain a safe angle.