Answer:
Step-by-step explanation:
Area of figure I = length * width
= 8 *16
= 128 cm²
Area of figure II = length * width
= 4 * 3
= 12 cm²
Trianlge:
base = b = 7 cm
height = 4 + 4 + 6 = 14 cm
[tex]\text{area of triangle =$\dfrac{1}{2}*b*h$}[/tex]
[tex]= \dfrac{1}{2} * 7 * 14[/tex]
= 7 * 7
= 49 cm²
Area of the figure = area of figure I + area of figure II + area of figure II
= 128 + 12 + 49
= 189 cm²[tex]\text{area of figure III = \dfrac{1}{2}*b*h}[/tex]
