Respuesta :

devishri1977

Answer:

Step-by-step explanation:

Area of figure I = length *width

                          = 4 * 5

                          = 20 m²

Figure II is a trapzium.

a and b  are the parallel sides. a = 21 m

b = 20 - 5 = 15 m

h =  3 + 4 = 7 m

[tex]\text{area of figure 2 = $\dfrac{(a + b)*h}{2}$}[/tex]

                       [tex]=\dfrac{(21+15)*7}{2}\\\\\\=\dfrac{36*7}{2}\\\\\\= 18*7\\\\= 126 \ m^{2}[/tex]

Area of the figure = 20 + 126

                               = 146 m²

Ver imagen devishri1977
semsee45

Answer:

146 m²

Step-by-step explanation:

Formulae

Area of a rectangle = width x length

Area of a triangle = 1/2 x base x height

Divide the figure into 2 rectangles and a triangle (see attachment).

Area of Rectangle 1 = 4 x 5 = 20 m²

Area of Rectangle 2 = (3 + 4) x (20 - 5) = 105 m²

Area of triangle 3 = 1/2 x (21 + 5 - 20) x (3 + 4) = 21 m²

Total area = 20 + 105 + 21 = 146 m²

Ver imagen semsee45

Otras preguntas