Answer:
= 0
Step-by-step explanation:
-3 = x^2 + 4x + 1
0 = x^2 + 4x + 4
a = 1
b = 4
c = 4
plug the numbers into the equation to find the discriminant value...
4^2 - 4(1)(4)
16 - 16 = 0
therefore your answer is 0
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Number of solution for the given quadratic equation as Discriminant=0 is equals to 1.
" Quadratic equation is defined as the polynomial containing variables with highest exponent equals to 2."
Formula used
For quadratic equation
[tex]ax^{2} +bx+c=0[/tex]
Discriminant = b²-4ac
According to the question,
Given quadratic equation
[tex]-3 = x^{2} +4x+1[/tex]
⇒[tex]x^{2} +4x+1 +3 =0[/tex]
⇒[tex]x^{2} +4x+4 =0[/tex]
Here, a=1 , b= 4 , c =4
Substitute the value in the formula we get,
Discriminant = [tex]4^{2} - 4(1)(4)[/tex]
= [tex]16 -16[/tex]
= 0
Number of solution discriminant =0 is 1.
[tex]x^{2} +4x+4 =0[/tex]
⇒[tex](x+2)^{2} =0[/tex]
⇒[tex]x= -2[/tex] has unique solution.
Hence, number of solution for the given quadratic equation as Discriminant=0 is equals to 1.
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