Can someone help me with these please


Answer:
1a. 210 m^2 1b. 14 ft^2 1c. 199.5 in^2
2a. 270 cm^2 2b. 162 m^2 2c. 272 cm^2
3a. 348 ft^2 3b. 230 in^2 3c. 312.5
Step-by-step explanation:
The area of a triangle can be calculated with one equation...
A = 1/2bh
b stands for base, h stands for height
1a. A = 1/2(21)(20)
One half divides 20 easily..
A = 21(10)
A = 210
1b. A = 1/2(7)(4)
One half divides 4 easily..
A = 2(7)
A = 14
1c. A = 1/2(19)(21)
A = 1/2(399)
A = 199.5
2a. A = 1/2(36)(15)
One half divides 36 easily..
A = 18(15)
A = 270
2b. A = 1/2(18)(18)
One half divides 9 easily..
A = 9(18)
A = 162
2c. A = 1/2(32)(17)
One half divides 32 easily..
A = 16(17)
A = 272
3a. A = 1/2(29)(24)
One half divides 24 easily..
A = 12(29)
A = 348
3b. A = 1/2(23)(20)
One half divides 20 easily..
A = 10(23)
A = 230
3c. A = 1/2(25)(25)
A = 1/2(625)
A = 312.5
Finding area of triangle --> [tex]\frac{1}{2}*b*h[/tex]
Question 1:
a. [tex]Area = \frac{1}{2}*b*h = \frac{1}{2}*20*21 = 210 m^2[/tex]
b. [tex]Area = \frac{1}{2}*b*h = \frac{1}{2}*4*7 = 14 ft^2[/tex]
c. [tex]Area = \frac{1}{2}*b*h= \frac{1}{2} *21*19=199.5in^2[/tex]
Question 2:
a. [tex]Area = \frac{1}{2}*b*h = \frac{1}{2} *36*15 = 270cm^2[/tex]
b. [tex]Area = \frac{1}{2}*b*h = \frac{1}{2} *18*18 = 162m^2[/tex]
b. [tex]Area = \frac{1}{2}*b*h = \frac{1}{2} *17*32 = 272cm^2[/tex]
Question 3:
a. [tex]Area = \frac{1}{2}*b*h = \frac{1}{2} *24*29 = 348ft^2[/tex]
b. [tex]Area = \frac{1}{2}*b*h = \frac{1}{2} *20*23 = 230in^2[/tex]
c. [tex]Area = \frac{1}{2}*b*h = \frac{1}{2} *25*25 = 312.5cm^2[/tex]
Finding Area of Parallelogram --> b * h
Question 1
a. [tex]Area = b * h = 24 * 26 = 624cm^2[/tex]
b. [tex]Area = b * h = 15 * 30 = 450in^2[/tex]
c. [tex]Area = b * h = 21 * 31 = 651 mm^2[/tex]
Question 2
a. [tex]Area = b * h = 18 * 17 = 306 in^2[/tex]
b. [tex]Area = b * h = 10.5 * 15 = 157.5m^2[/tex]
c. [tex]Area = b * h = 12.5*11=137.5cm^2[/tex]
Question 3:
a. [tex]Area = b * h = 5.7*11.5=65.55in^2[/tex]
b. [tex]Area = b * h = 8 * 12.5 = 100ft^2[/tex]
c. [tex]Area = b * h = 1.7 * 3.6 = 6.12m^2[/tex]
Hope that helps!