The test statistic and p-value of the given data are 6.274 and 0.0001 respectively.
The test statistic can be calculated using the formula below
[tex]t = \frac{x-\mu}{\sigma / \sqrt{n} }[/tex]
Solving for the mean and standard deviation, we can substitute the values into the above equation which will be
[tex]t = \frac{x-\mu}{\sigma / \sqrt{n} } = 6.274[/tex]
Using the data from the test statistic, we can calculate the p-value of the data
[tex]p-value = p(z < 6.274)= 0.0001 = 0.00[/tex]
From the calculation above, the test statistic and p-value of the given data are
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