8305 grams of HNO3 would be needed to prepare 5.5L of a solution. Details on how to calculate mass is found below.
The mass of a substance in a solution can be calculated using the following formula:
Density = mass ÷ volume
According to this question, 5.5L of a HNO3 solution is given.
Density of HNO3 is 1.51 g/cm³
Volume of HNO3 = 5500mL
1.51 = mass/5500
mass = 8305g
Therefore, 8305 grams of HNO3 would be needed to prepare 5.5L of a solution.
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