For a volume of 27,000 L to a pressure of 0.82 atm at 25 °C, the amount of N2 is required is mathematically given as
n=1.1*10^{-3}mole
What amount of N2 is required to fill a small room with a volume of 27,000 L to a pressure of 0.82 atm at 25 °C?
Generally, the equation for the ideal gas is mathematically given as
PV=nRT
Therefore
[tex]n=\frac{PV}{RT}\\\\n=\frac{0.980*2700}{0.0821*298}[/tex]
n=1.1*10^{-3}mole
In conclusion, the amount of N2 is required is
n=1.1*10^{-3}mole
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