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Answer:

The first one i would think might be 0.05? uncertian and probably wrong, the second, HHH, HHT, HTH, HTT, THH, THT, TTH, and TTT, and the third, 3/8.

The way you figure out the third one is you are flipping 3 coins still, and you take all of the options above and there are 8 total and 3 ov them would land you 2 heads and a tail so its a simple 3/8 fraction

semsee45

Answer:

2.  0.05

3. a) 8 outcomes (listed below)

3. b) 3/8

Step-by-step explanation:

Question 2

The sum of the probabilities of all possible outcomes is 1.

Therefore, if the probability of being on time for class is 0.95, then the probability of NOT being on time for class is:

1 - 0.95 = 0.05

Question 3

a)  8 possible outcomes of flipping 3 coins (H = heads, T = tails):

HHH     HHT     HTH     THH

TTT       TTH     THT      HTT

b)  

There are 3 possible ways of flipping 2 Heads and 1 Tail:

HHT    HTH     THH

Out of a total number of 8 possible outcomes.

[tex]\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}[/tex]

[tex]\sf \implies P(2\:Heads\:and\:1\:Tail) = \dfrac38[/tex]

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