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A random sample of banana tree yields has a sample mean of x=67 banana and sample standard deviation of s= 2 bananas. Use the empirical rule to estimate the percentage of banana yields that are less than 61 bananas. Round your answer to the nearest hundredth.

Respuesta :

Using empirical rule, 99.85% of the data falls above 61

Data;

  • Mean = 67
  • standard deviation = 3

Empirical Rule

Using empirical rule, it states that 68% of data is within 1 standard deviation from the mean mean± standard deviation 95% of data falls within 2 standard deviations from the mean mean± 2* standard deviation and 99.7% of data falls within 3 standard deviations from the mean mean± 3sd . So we can say that 0.15% of data are below mean minus 3 * standard deviation and 0.15% of data are above mean+3sd. In this case, the mean is 67 , SD = 3.

And if 61 is 3×SD below mean

[tex]Pr(X > 61)=1-Pr(X\leq 61) = 1 - 0.0015 = 0.9985\\1-0.0015=0.9985[/tex]

99.85% of data is above 61

Learn more about empirical rule here;

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