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A lamp is 15% efficient. How much electrical energy must be supplied to the lamp each second if it produces 30 J of light energy per second? *WILL MARK BRAINLIEST*

Respuesta :

fieryanswererft

200 Joules should be supplied in the circuit.

  • Efficiency = output/inupt

Here the output is 30J and input is missing

[tex]\sf \dfrac{30}{I} * 100 = 15[/tex]

multiplied with 100, to covert it into percentage

[tex]\sf 3000 = 15(I)[/tex]

[tex]\sf I = \dfrac{3000 }{15}[/tex]

[tex]\sf I = 200J[/tex]

Let that be X

  • Efficiency is 15% means the lamp produces 15J of light energy when 100J energy applied.

[tex]\\ \rm\Rrightarrow \dfrac{30}{x}(100)=15[/tex]

[tex]\\ \rm\Rrightarrow 3000=15x[/tex]

[tex]\\ \rm\Rrightarrow x=200J[/tex]

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