Martin is saving money to buy a new phone that costs $1,000 by selling trees. He is using an app to manage his
sales, but it keeps a fraction of each sale. His net pay is modeled by the function P(x) = x2 + 20x– 196, where x
represents the number of sales. How many sales does Martin need to make to earn $1,000?

Respuesta :

Answer: 26 sales

Step-by-step explanation:

If you plug in 26 you will get exactly $1,000

Martin needs to sale 8 pieces to make it $1000.

How to elaborate the problem ?

Martin has to save $1000.

He is using an app to manage all the sales, but if keeps fraction of every sales.

The equation which represents his net pay is P(x)=[tex]x^{2}+20x-196[/tex]

How many sales does martin need ?

We have to solve the given quadratic equation.

Here, x= (-b±[tex]\sqrt{ b^{2}-4ac }[/tex])/2a

⇒ x= (-20±[tex]\sqrt{400+4*196}[/tex])/2

⇒ x= (-20±[tex]\sqrt{1184}[/tex])/2

⇒ x= -10±[tex]\sqrt{296}[/tex]

⇒ x= -10±17.2

We habe to take the maximum value of x. So we neglect the negative sign.

Hence, x= -10+17.2 = 7.2 = 8 (approx) ,here we can not take 7 because if he sales 7 pieces then the money should less than $1000.

Learn more about Quadratic equation here :

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