Answer:
C) The discriminant is greater than 0, so there are two real roots
Step-by-step explanation:
Discriminant
[tex]b^2-4ac\quad\textsf{when}\:ax^2+bx+c=0[/tex]
[tex]\textsf{when }\:b^2-4ac > 0 \implies \textsf{two real roots}[/tex]
[tex]\textsf{when }\:b^2-4ac=0 \implies \textsf{one real root}[/tex]
[tex]\textsf{when }\:b^2-4ac < 0 \implies \textsf{no real roots}[/tex]
[tex]2x^2-9x+2=-1[/tex]
[tex]\implies 2x^2-9x+3=0[/tex]
[tex]\implies a=2, b=-9, c=3[/tex]
[tex]\begin{aligned}b^2-4ac &=(-9)^2-4(2)(3)\\& =81-24\\&=57 > 0\implies \textsf{two real roots}\end{aligned}[/tex]
