For this right triangle, what is the cosine of angle C?

Answer:
cos C = [tex]\frac{12}{13}[/tex]
Step-by-step explanation:
this is a 5- 12- 13 right triangle with BC = 12 , then
cos C = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{BC}{AC}[/tex] = [tex]\frac{12}{13}[/tex]