Using the Central Limit Theorem, it is found that the sampling distribution of o is approximately normal with mean 0.58 and standard error of 0.0698.
It states that for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1 - p)}{n}}[/tex], as long as [tex]np \geq 10[/tex] and [tex]n(1 - p) \geq 10[/tex].
In this problem, we have that the proportion and the sample size are given as follows: p = 0.58, n = 50.
Hence, the mean and the standard error are given by:
[tex]\mu = p = 0.58[/tex].
[tex]s = \sqrt{\frac{0.58(0.42)}{50}} = 0.0698[/tex]
More can be learned about the Central Limit Theorem at https://brainly.com/question/24663213
#SPJ1
